Prove: (1+tan?)(1+ sin 0) (1 - sin 6) = 1.
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(1+tan
2
θ)(1−sinθ)(1+sinθ)
=(sec
2
θ)(1−sin
2
θ)
=(sec
2
θ)(cos
2
θ)
=(sec
2
θ)(
sec
2
θ
1
)
=1
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