Prove 1- tan theta/1+ tan theta= cos theta- sin theta
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Given, edxdy=x+1
dxdy=log(x+1)
Integrating both sides
y=∫log(x+1)dx.
Put x+1=t⇒dx=dt
y=∫logtdt=tlogt−t+c
⇒y=(x+1)log(x+1)−(x+1)+c
Put x=0,y=3⇒c=4
∴y=(x+1)log(x+1)−x+3
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