Question

prove

(1 + tanA) ^2 + ( 1- tanA)^2 = 2sec A

Answer 1

Hello,

we must show that:

(1+tanA)²+(1-tanA)²=2 sec²A

we consider the first member:

(1+tanA)²+(1-tanA)²

we have that:

(1+tanA)²+(1-tanA)²;

= 1+tan²A+2tanA+1+tan²A-2tanA;

=2+2tan²A

being sen²A-tan²A=1 that is

sec²A=1+tan²A;

so you have:

2+2tan²A;

=2(1+tan²A);

=2sec²A

Hope this helps you ☺️☺️❤️❤️✌️✌️

Answer 2

hey❤

here is ur answer!!

please refer to the attachment :))

hope it helps!!

thanks☺☺☺