prove 1/x + 1/y =1/z
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please check whether it is
1/x+1/y =1/z or
1/x+1/z = 1/y
Step-by-step explanation:
since PA, QB and RC are perpendicular on AC, they are parallel to each other also.
now in triangles PAC and QBC
angle PCA = angle QCB (common)
angle PAC = angle QBC (90°)
angle APC = angle BQC (corresponding angle)
hence the two triangles are similar
so, PA/QB = AC/BC
AC/BC = x/y
or, BC/AC = y/x........(1)
similarly we can prove that triangles RCA and QBA are similar hence,
AC/AB = RC/QB
AC/AB = z/y
or, AB/AC = y/z.......(2)
adding (1) and (2)
BC/AC + AB/AC = y/x + y/z
(BC+AB)/AC = y(1/x+1/z)
AC/AC = y(1/x+1/z). (AB+BC= AC)
1 = y(1/x+1/z)
1/y = 1/x+1/z
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