Question

prove 100-100/100-100 is equal to two

Answer 1

hey!

here is your Answer
we can write as

$\frac{1 {0}^{2} - 1 {0}^{2} }{10(10 - 10)} \\ \\ use \: the \: identity \\ a {}^{2} - {b}^{2} \\ \\ now \\ \\ \frac{(10 + 10)(10 - 10)}{10(10 - 10)} \\ \\ = \frac{20(10 - 10)}{10(10 - 10)} \\ \\ = \frac{20}{10} \\ \\ = 2 \: hence \: proved$

Answer 2

Hey!
There is a glitch in the question, Actually, If you try to solve it, You'll get 0/0, which, Ofcourse is undefined.
Anyways, The way you want me to do is


$\frac{ {10}^{2} - {10}^{2} }{10(10 - 10)} \\ \\ = (10 + 10)(10 - 10) \div 10(10 - 10) \\ \\ = \frac{(10 + 10)(0)}{10(0)} \\ \\ = error$

Here, if you cancel out (10-10), You are actually dividing it by 0 again.

So better focus on what's real, And don't run behind many such glitches.