Prove 1J=10^7erg
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1 Joule=107 erg
Let 1 joule=n2 erg
n2= 1 joule/ erg
therefore:- [M1L1T1-2] /[M2L2T2-2]
[M1/M2] [L12/L12] [T1-2/ T2-2]
[kg /gm] [m/cm]2 [s/s]-2
[103gm/gm] [102cm/cm] [-1]-2
[103][104][10]
[107]
Here I used dimensions of units.
It can also be solved in this way -
Since 1 erg = 1 g·cm2/s2
1 joule = 1 kg.m2/s2 = 103 g x (100 cm)2 /s2=107 g·cm2/s2 = 107 erg.
Let 1 joule=n2 erg
n2= 1 joule/ erg
therefore:- [M1L1T1-2] /[M2L2T2-2]
[M1/M2] [L12/L12] [T1-2/ T2-2]
[kg /gm] [m/cm]2 [s/s]-2
[103gm/gm] [102cm/cm] [-1]-2
[103][104][10]
[107]
Here I used dimensions of units.
It can also be solved in this way -
Since 1 erg = 1 g·cm2/s2
1 joule = 1 kg.m2/s2 = 103 g x (100 cm)2 /s2=107 g·cm2/s2 = 107 erg.
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