Question

Prove 2+5 = 10.........

Answer 1

Let x = y

Multiplying both sides by x

x² = xy

Subtract y² from both sides

x²-y²=xy-y²

(x+y)(x-y) = y(x-y)

x+ y = y[ we know that x = y ]

y + y = y

2y = y subtract from both sides

2y - y = y-y

1*y = 0*y

1 = 0.

Now,


2 + 5

= 2 + 5 + 0 + 0 + 0

Substitute 0 = 1 .

= 2 + 5 + 1 + 1 + 1

= 10

Hence proved! 2 +5 = 10

Answer 2

Prove that 2+2=10

Proof :- We know that 2+2=4 - (eq. 1)

$= > 2 + 2 = 4 + \frac{9}{2} - \frac{9}{2 } \\ = \sqrt{(4 - \frac{9}{2} } ) {}^{2} + \frac{9}{2} \\ = \sqrt{ - 20 + \frac{81}{4} } + \frac{9}{2} \\ = \sqrt{25 - 45 + \frac{81}{4} } + \frac{9}{2} \\ = \sqrt{5 {}^{2} - 2.5. \frac{9}{2} } + \frac{9}{2} \\ = \sqrt{(5 - \frac{9}{2} ) {}^{2} } + \frac{9}{2} \\ = 5 - \frac{9}{2} + \frac{9}{2} \\ = 5 \\ 2 + 2 = 5 \: \: (eq - 2)$

From Eqs 1 & 2,we obtain
5+4=9

Dividing both sides by 3,
$\frac{5 + 4}{3} = \frac{9}{3} \\ 5 + 4 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 \\ 5 + 4 = 10 \\ 5 + \sqrt{4} = 10 \: \: (taking \: \sqrt{} root \: on \: 4) \\ 5 + 2 = 10 \\ 2 + 5 = 10$
Answer- Hence proved that 2+5=10.

But always remember, In Mathematics, a statement is only accepted or valid, if it is either true or false. We say that a statement is true, if it is always true otherwise it is called a false statement.

For example, 5+2=7 is always true, so '5+2=7' is a true statement and 5+3=7 is a false statement.