Math, asked by thirumaniselvir, 1 month ago

prove 2√5-3 is an irrational number​

Answers

Answered by mithileshcrucio
0

Let us assume to the contrary that 2√5 -3 is a rational number .

Now then 2√5-3 = a/b ( where a and b are co primes)

2√5 -3 = a/b

2√5 = a/b +3/1

√5 = a/2b +3/2 ( mark this 1)

From 1 we can see that √5 is a rational number. But we know √5 is a irrational number. This contradicts our assumption that a and b are co primes.

Hence 2√5 -3 is a irrational number

Answered by darkrockinggamers
0

Answer:

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