prove √2 is irrational
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To prove that the square root of 2 is irrational is to first assume that its negation is true. Therefore, we assume that the opposite is true, that is, the square root of 2 is rational. ... So, 2 = a b \sqrt 2 = {\Large{{a \over b}}} 2 =ba where a and b are integers but b ≠ 0 b \ne 0 b=0.
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