Prove 2 sin square theta+4 sec squaretheta +5 cot squaretheta + 2 cos square theta- 4 tan square theta -5 cosecSquare theta =1
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Solution :
Here, I am using A instead of theta.
**********************************
We know the Trigonometric identities:
i ) sin²A + cos²A = 1
ii ) sec²A - tan² A = 1
iii ) cot²A-cosec²A = -1
***************************************
LHS = 2sin²A+4sec²A+5cot²A
+ 2cos²A-4tan²A-5cosec²A
= 2(sin²A+cos²A)+4(sec²A-tan²A)
+5( cot²A - cosec²A )
= 2 × 1 + 4 × 1 + 5 × ( -1 )
= 2 + 4 - 5
= 6 - 5
= 1
= RHS
•••••
Here, I am using A instead of theta.
**********************************
We know the Trigonometric identities:
i ) sin²A + cos²A = 1
ii ) sec²A - tan² A = 1
iii ) cot²A-cosec²A = -1
***************************************
LHS = 2sin²A+4sec²A+5cot²A
+ 2cos²A-4tan²A-5cosec²A
= 2(sin²A+cos²A)+4(sec²A-tan²A)
+5( cot²A - cosec²A )
= 2 × 1 + 4 × 1 + 5 × ( -1 )
= 2 + 4 - 5
= 6 - 5
= 1
= RHS
•••••
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