Prove 2as= v2-u2 by dimension formula.
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i know graphical and arithmatic method.. if u r trying to ask the third equation of motion... tell me if it is third eq. of motion
durvasharma576:
You don't know how to solve this??
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dimension of
2as = m*m/s*s = m^2/s^2 ......i)
v^2 - u^2
here v and u both stand for velocity hence their dimensional Formula will be same
v^2 = u^2 = (m/s)^2 = m^2/s^2 ......ii)
from equation i) and ii) it's proved that
DIMENSION OF RHS = DIMENSION OF LHS
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