Question

prove 2root5 is irrational by using contradiction method​

Answer 1

Step-by-step explanation:

Let us suppose that 2√5 is rational

Then, 2√5 = a/b (where a&b are rational and co-prime)

√5=a/2b

Here, On RHS

a and 2b are Real & a/2b is Rational

Thus, LHS or √5 is also Rational

But this contradicts the fact that √5 is Irrational

Hence, our Supposition was Wrong

Therefore, 2√5 is IRRATIONAL