Math, asked by abhaattara50, 2 months ago

prove 3√2 + 2 is irrational​

Answers

Answered by abhijithajare1234
28

Answer:

Answer. 3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational..

Answered by BrainlyBAKA
5

Prove :

Let 3+√2 is an rational number.. such that 3+√2 = a/b , where a and b are integers and b is not equal to zero .

therefore,

3 + √2 = a/b

√2 = a/b -3

√2 = (3b-a) /b

therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..

It means that √2 is rational....

But this contradicts the fact that √2 is irrational..

So, it concludes that 3+√2 is irrational..

hence proved..

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