prove 3√2 + 2 is irrational
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Answered by
28
Answer:
Answer. 3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational..
Answered by
5
Prove :
Let 3+√2 is an rational number.. such that 3+√2 = a/b , where a and b are integers and b is not equal to zero .
therefore,
3 + √2 = a/b
√2 = a/b -3
√2 = (3b-a) /b
therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..
It means that √2 is rational....
But this contradicts the fact that √2 is irrational..
So, it concludes that 3+√2 is irrational..
hence proved..
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