Question

prove 3=2 ? Let's see who can???​

Answer 1

Step-by-step explanation:

Let 2 equation be x³+x²+3x=0 & x³+x²+2x=0.

Put x=0 in both equation to prove LHS=RHS.

NOW, take first equation x³+x²+3x=0, x³+x²+2x=0.

Now take x common from both the equations.

x²+x+3=0, x²+x+2=0.

Both equations are equal to zero. So we can make both equation equal.

x²+x+3=x²+x+2

x²+x-x²-x+3=2

So, 3=2

HENCE PROVED

Answer 2

Answer:

Let 2 equation be x³+x²+3x=0 & x³+x²+2x=0.

Put x=0 in both equation to prove LHS=RHS.

NOW, take first equation x³+x²+3x=0, x³+x²+2x=0.

Now take x common from both the equations.

x²+x+3=0, x²+x+2=0.

Both equations are equal to zero. So we can make both equation equal.

x²+x+3=x²+x+2

x²+x-x²-x+3=2

So, 3=2

HENCE PROVED