prove 3√2irrational number
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let 3√2 be a rational number.
3√2 = p/q (where p and q are integers and q is not equal to zero)
√2 = p/3q
We know that the product left after dividing two rational number is rational but here √2 is irrational.
So, our assumption is wrong.
3√2 is an irrational number.
3√2 = p/q (where p and q are integers and q is not equal to zero)
√2 = p/3q
We know that the product left after dividing two rational number is rational but here √2 is irrational.
So, our assumption is wrong.
3√2 is an irrational number.
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