Question

Prove ( 3+ 5w + 3w ^2 ) ^ 6 = 64

Answer 1

Answer:

$\left(3+5w+3w^2\right)^6=64\quad :\quad w=\frac{-5+\sqrt{13}}{6},\:w=\frac{-5-\sqrt{13}}{6}$

Step-by-step explanation:

$\left(3+5w+3w^2\right)^6=64$

$\mathrm{For\:}\left(g\left(x\right)\right)^n=f\left(a\right)\mathrm{,\:n\:is\:even,\:the\:solutions\:are\:}g\left(x\right)=\sqrt[n]{f\left(a\right)},\:-\sqrt[n]{f\left(a\right)}$

$w=\frac{-5+\sqrt{13}}{6},\:w=\frac{-5-\sqrt{13}}{6}$