Question

Prove 3 Equations of Motion Algebraically​

Answer 1

Answer:

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Answer 2

• V = U + AT

acceleration= change in velocity/ time taken

A = v - u/ t

at= v- u

v = u+ at

• S= Ut+ ½ at ²

Average velocity= initial + final velocity /2

A.V = u+ v /2

distance travelled = a.v× t

S= [u+v]/2×t

from first equation of motion putting the value of v

S= [u + v + at]/2×t

S= 2u + at²/2

S= 2ut/2+½at cancel 2..2

S= ut+ ½ at ²

• V²=u²+2 as

from 2nd equation of motion

S= ut +½ at ²

and from 1st equation of motion

V = U + AT

T = V - U / A

putting the valve t in second equation of motion

V²= u(v-u) /A +½A(v-u) /A

S= UV - u²/A + A ( v²- 2uv+u²/2a²

S = uv-u² / A + v² + u² -2uv/2a

S = 2uv-2u²+v²+u²-2uv/2a

2as= v²- u²

V²= U²+ 2 as