Question

prove √3 is an irrational number

Answer 1

Let us assume that √3 is a rational number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

by squaring both the side

(√3q)² = p²

3q² = p² ........ ( i )

So,if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,if 3 is factor of q²

then, 3 is also factor of q

Since,3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

Hence, √3 is an irrational number.

_______________

@zaqwertyuioplm :)