prove √3 is an irrational number
Answers
Answered by
1
Hope it's helpful to you.
Please mark as Brainlist answer.
Attachments:
Answered by
0
Answer:
Plz mark as brainalist if it is helpfull to you.
Assume that root 3 is rational
So, root 3 =a/b ( where a and b are
co- prime)
(root 3b)^2 = a
3b^2 = a .........(eqn 1)
Now, 3 divides a^2 therefoe by theorum 1.3 3divides a.
Let, a/3 = c (where c is some
integer)
a = 3c
by putting a= 3c in (eqn 1)
3b^2 = (3c)^2
3b^2 = 9 c^2
b^2 = 3c ^2
Now,3 divides b^2. Therefore, by theorum 1.3 3 divides b
This contradicts that our assumption is wrong ant root 3 is irrational.
HOPE IT HELPS YOU
Plz mark as brainalist.
Similar questions