Prove √3 is Irrational
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Then √3 = p/q, where p, q are the integers i.e., p, q ∈ Z and co-primes, i.e., GCD (p,q) = 1. Here 3 is the prime number that divides p2, then 3 divides p and thus 3 is a factor of p. ... So, √3 is not a rational number. Therefore, the root of 3 is irrational.
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