Question

prove 3 + root 5 is irrational
$3 + \sqrt{5}$
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Answer 1

let 3+√5 be a rational number.

3+√5 = p/q (where p and q are integers and q is not equal to zero)

√5 = p/q-3

We know that the difference of rational number is rational but here the difference is irrational, because we already know that √5 is irrational and the difference of rational number is rational but here √5 is irrational.

So, Our assumption is wrong.

3+√5 is an irrational number.

Answer 2

Answer:

Step-by-step explanation: