prove √3sin∅ + cos∅ = 2
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√3sinθ + cosθ = 1
Divide by 2 to get (√3/2)sinθ + (1/2)cosθ = 1/2
cos(π/6)sinθ + sin(π/6)cosθ = 1/2
sin(π/6+θ) = 1/2
So, π/6 + θ = π/6 or 5π/6
θ = 0 or 2π/3
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