prove 5+3√2 is irrational
sowmyameruva:
A number that cannot be expressed as a ratio between two integers and is not an imaginary number. If written in decimal notation, an irrational number would have an infinite number of digits to the right of the decimal point, without repetition. as we know √2 =1.4141.41421 35623 73095 0488..... so there fore it is irrational. :)
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Answered by
4
Hey.. I think this can be ur answer!!
Let us assume that 5+3root2 is rational
So,
5 +3root2 =a/b
3root2 =a /b - 5 =a-5b/b
Root2 = a-5b /3b
But we know that root2 is irrational
So our assumption was wrong
Hence, 5+3root2 is irrational
Hence proved
Hope it helps you dear ☺️☺️
Let us assume that 5+3root2 is rational
So,
5 +3root2 =a/b
3root2 =a /b - 5 =a-5b/b
Root2 = a-5b /3b
But we know that root2 is irrational
So our assumption was wrong
Hence, 5+3root2 is irrational
Hence proved
Hope it helps you dear ☺️☺️
Thank u
my pleasure :)
Answered by
1
lets assume 5+3√2 is an rational number
divide 5+3√2 by a&b to get the common factor
5+3√2 = a\b
3√2 = a\b - 5
√2 = a - 5b\3b
irrational is not equal to rational
our supposition went wrong it's an irrational number
divide 5+3√2 by a&b to get the common factor
5+3√2 = a\b
3√2 = a\b - 5
√2 = a - 5b\3b
irrational is not equal to rational
our supposition went wrong it's an irrational number
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