prove √5 is an irrational number
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3
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to the contrary let us assume that √5 is ratuonal so it can be expressed in from of p/q where p and q are co prime integer
√5 = p/q
squaring both side..
√5² = (p/q)²
5 = p² / q²
5q² = p². ....(1)
p² is divisible by 5
p is divisible by 5 ...(2)
put p = 5c in eq..(1)
5q² = (5c)²
q²= 25c²/5
q²= 5c²
q² is divisible by 5
q is divisible by 5 .... (3)
from eq.1 and eq..2 we get that p and q have common factor 5 but this contradicts the fact that p and q are co prime ....
so this contradiction arisen due to our wrong assumption that√5 is rational
therefore √5 is irrational
hence proved. ....
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Answered by
7
Answer:
hey mate sry .......
here is Ur answer ,.....
bye
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