Question

prove √7 is irrational number ​

Answer 1

Answer:

hii

Step-by-step explanation:

take √7 is rational number and a,b is co prime number

√7=a/b

√7b =a

square on both sides

7b^2=a^2

7 is divided by a^2

7 is divided by a

a=7c

square on both the. side

a^2= 49c^2

7b^2=49c^2 (from above )

b^2=7c^2

hence we can see a and b are not coprime

hence our contradiction is wrong √7 is irrational

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