Question

prove A(0,0)B(5,0)c(5,5)D(0,5)are vertices of a square​

Answer 1

Answer:

Step-by-step explanation:

distance of ab = root of (0-0)^2 + (0-0)^2

                   ab =   0 units

   bc = root of (0-0)^2 + (0-0)^2

        bc= o units

by this all sides are equal

now ac = root of 0-0 square + 0-0 square

ac=0

bc=0

all sides are equal and both diagonals are equal so its a square

Answer 2

Answer:

47tbfju588hjj

Step-by-step explanation:

tu6+3y=379