Math, asked by gudiseabhishek007, 1 year ago

prove a^0 is 1 with steps

Answers

Answered by PSN03
2

let a=2

2^1=2

2^2=4

2^3=8

2^4=16

now

2^4/2=16/2=8=2^3

2^3/2=8/2=4=2^2

2^2/2=4/2=2=2^1

2^1/2=2/2=1

this should be equal to 2^0 due to the pattern observed

therefore a^0=1

(if u  want this completely in terms of a then just replace 2 with a)

hope this helps

:)

Answered by mkrishnan
1

a^0= a/a = 1

a^5=a^7/a^2 for example

but a is not equal to 0

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