Question

prove ( a+b )^2=?????​

Answer 1

Answer:

$\large{\underline{\boxed{\sf (a + b)^2 = a^2 + 2ab + b^2 }}}$

Step-by-step explanation:

$\tt (a + b)^{2} \\ \\ \implies \tt (a + b)(a + b) \\ \\ \implies \tt {a}^{2} + ab + ab + {b}^{2} \\ \\ \implies \tt {a}^{2} + 2ab + {b}^{2}$

Hence,

$\boxed{ \therefore \: \bf (a + b) {}^{2} = a {}^{2} + 2ab + {b}^{2} }$

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Now, see the use of this identity,

Let a = 2 and b = 4,

⇒ (2 + 4)²

⇒ 6²

⇒ 36

Now,

$\tt (a + b) {}^{2} \\ \\ \implies \tt (2 + 4) {}^{2} \\ \\ \implies \tt (2) {}^{2} + 2 \times 2 \times 4 + (4) {}^{2} \\ \\ \implies \tt 4 + 16 + 16 \\ \\ \implies \tt 36$

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Hence, (a + b)² = a² + 2ab + b².

Answer 2

Answer:

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