Question

prove (a+b)^2=(a-b)^2+4ab

Answer 1

a2+b2+2ab= a2+b2-2ab
a2+b2+4ab = a2+b2
(a+b)(a-b)+4ab = (a+b)(a-b)
{{(a+b)(a-b)= a2-b2=( a-b)^2 }}}
(a-b)^2+ 4ab = (a+b)^2

Answer 2

Answer:

$(a+b)^{2}=(a-b)^{2}+4ab$

Step-by-step explanation:

$RHS = (a-b)^{2}+4ab\\</p><p>=a^{2}+b^{2}-2ab+4ab\\=a^{2}+b^{2}+2ab\\=(a+b)^{2}\\=LHS$

Therefore,

$(a+b)^{2}=(a-b)^{2}+4ab$

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