Question

Prove (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0​

Answer 1

Answer:

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Answer 2

Answer:

we know,

(a – b) (a + b) = a2 - b2

(b – c) (b + c) = b2 - c2

(c – a) (c + a) = c2 - a2

putting the values in equation, we get

(a2 - b2) + (b2 - c2) + (c2 - a2)

a2 - a2 +b2 - b2 + c2 - c2

= 0

as lhs = rhs

hence (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0 is proved

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