Question

prove: a circle with O had chord AB congruent to chord CD also CD is perpendicular to AB and On is perpendicular to chord CD​

Answer 1

Answer:

Answer:

∠OMN=∠ONM (Hence Proved)

Step-by-step explanation:

Given: AB and CD are equal chords of a circle whose center is O. OM is perpendicular to AB and ON is perpendicular to CD.

To prove: ∠OMN=∠ONM

Figure: Please see the attachment

Theorem: If chords are equal of same circle then they are equidistance from center.

AB = CD

OM is distance of chord AB from center.

ON is distance of chord CD from center.

OM=ON (If chords are equal of same circle then they are equidistance from center)

In ΔMON, OM=ON

∠OMN=∠ONM , In a triangle if opposite sides are equal then their corresponding angles are equal.

Answer 2

Answer:

Hope these attachments helps you