Prove. (a^m)^n = (a^n)^m
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LHS
(a^m)^n
=>a^mn
RHS
(a^n)^m
=>a^nm
a^mn=a^nm
hence proved
Answered by
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Answer:
it is true
by an eg we can illustrate this
(2^2)^3=4^3=64
(2^3)^2=8^2=64
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