Prove A n (B-C)=(A n B) - (A n C)
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As we know that
A−B=A∩B′
And also (A∩B)′=A′∪B′,A∩(B∪C)=(A∩B)∪(A∩C)
A−(B∩C)=A∩(B∩C)′=A∩(B′∪C′)=(A∩B′)∪(A∩C′)=(A−B)∪(A−C)
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