prove - a square + b square = (a square + b square) - 2ab
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0
Answer:
Step-by-step explanation:
a² + b ² = (a + b)² - 2ab
= (a + b)(a + b) - 2ab
= a² + 2ab + b² - 2ab
= a² + b² + 2ab - 2ab by the Commutative Property of Addition.
= a² + b² + 2ab + (- 2ab) by the Definition of Subtraction.
= a² + b² + [2ab + (- 2ab)] by the Associative Property of Addition.
= a² + b² + 2[ab + (- ab)] by the Distributive Property.
= a² + b² + 2[0] by the Additive Inverse Property.
= a² + b² + 0 by the Multiplication Property of Zero.
= a² + b²
Answered by
1
Step-by-step explanation:
not (a²+b²)
but (a-b)² = a²+b²-2ab
ok.
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