Question

prove :- a2-2ab+b2=(a-b)2​

Answer 1

Step-by-step explanation:

$\implies$ $\sf{ a^2-2ab+b^2 = (a-b)^2}$

$\implies$ $\sf{a^2-2ab+b^2=(a-b)(a-b) }$

$\implies$ $\sf{a^2-2ab+b^2 = a(a-b)-b(a-b) }$

$\implies$ $\sf{a^2-2ab+b^2 =a^2 - ab -ab +b^2 }$

$\implies$ $\sf{ a^2-2ab+b^2 =a^2 -2ab+b^2}$

$\therefore$ $\sf{LHS = RHS }$

Hence, proved.

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