Question

prove a3+b3=(a+b)(a2-ab+b2)​

Answer 1

id of (a+b)^3

a^3 + b^3 + 3a^2b + 3ab^2 = (a+b)^3

a^3 + b^3 = (a+b)^3 -3ab(a+b)

will be an another identity

and

(a+b)(a2-ab+b2)= a^3 + b^3

a^3 -a^2b + ab^2 +a^2b +-ab^2 + b^3

= a^3 + b^3

hence proved

Answer 2

Step-by-step explanation:

id of (a+b)^3

a^3 + b^3 + 3a^2b + 3ab^2 = (a+b)^3

a^3 + b^3 = (a+b)^3 -3ab(a+b)

will be an another identity

and

(a+b)(a2-ab+b2)= a^3 + b^3

a^3 -a^2b + ab^2 +a^2b +-ab^2 + b^3

= a^3 + b^3

hence proved

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