Question

Prove AB and DE are parallel in a corresponding angle

Answer 1

Answer:

Step-by-step explanation:

In △ACB and △DCE,

∠ACB=∠DCE (Vertically opposite angles)

∠CAB=∠CED (Alternate angles to parallel lines AB and DE)

∠CBA=∠CDE (Alternate angle to parallel lines AB and DE)

Thus, △ACB≅△ECD,

hence,  

CE

AC

​  

=  

CD

CB

​  

 (Corresponding sides)

15

6

​  

=  

CD

BC

​  

 

CD

BC

​  

=  

5

2

​  

 

Let BC=2x and CD=5x

Given BD=28

BC+CD=28

2x+5x=28

7x=28

x=4

Thus, BC=8 cm and CD=20 cm