Question

Prove: ABCD is a parallelogram and BD=AC
Prove ABCD is a rectangle.

Answer 1

Answer:

Let given parallelogram is ABCD whose diagonals AC and BD are equal, i.e., AC = BD. Now, we have to prove that ABCD is a rectangle. But DC || AB and transversal CB intersect them. Thus, ABCD is a parallelogram and one of angles is 90°.

Step-by-step explanation:

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