Question

prove abIIef
plppsjdjdnjfjfjd​

Answer 1

Answer:

First you will get [CED]as 32° .

Step-by-step explanation:

Then you can find [CDE] which is 112° .

Extend ED UNTIL X.

Now angle [BDX] will be 112° by v.o.a .

As the adjacent angles are supplementary the lines can be said parallel .

FOLLOW if useful ..

Answer 2

Step-by-step explanation:

angle DEC = 180 - 148 = 32 °

( linear pair of angles)

In ∆ DEC

angle DEC + angle ECD + angle CDE = 180°

(angle sum property of ∆ )

= angle CDE = 180 - (32+26)

= 180 -68

= 112 °

Here, angle BDE + angle CDE = 180

(linear pair)

angle BDE = 180 -112

angle BDE = 68°

Since angle ABC = angle BDF

(they form alternate angles)

So AB parallel to EF