prove additive law of probability
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The addition rule for probabilities describes two formulas, one for the probability for either of two mutually exclusive events happening and the other for the probability of two non-mutually exclusive events happening. The first formula is just the sum of the probabilities of the two events.
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ANSWER
Addition theorem of probability →
If A and B are any two events then the probability of happening of at least one of the events is defined as
P(A∪B)=P(A)+P(B)−P(A∩B)
Proof:-
From set theory, we know that,
n(A∪B)=n(A)+n(B)−n(A∩B)
Dividing the above equation by n(S) both sides we have,
n(A∪B)/n(s) = n(A)/n(s) + n(B)/n(s) − n(A∩B)/n(s)
P(A∪B)=P(A)+P(B)−P(A∩B)
(∵P(X)= n(X)/n(s)
Hence proved .
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