Question

prove algebracally : ( x'+y'+z)(x'+y+z)(x+y+z)​

Answer 1

Answer:

L.H.S. = (X + Y)(X + Z) = XX + XZ + XY + YZ = X + XZ + XY + YZ (XX = X Indempotence law) = X + XY + XZ + YZ = X(1 + Y) + Z(X + Y) = X.1 + Z(X + Y) (1 + Y = 1 property of 0 and 1) = X + XZ + YZ) (X . 1 = X property of 0 and 1) = X(1 + Z) + YZ = X.1 + YZ (1 + Z = 1 property of 0 and 1) = X.1 + YZ (X . 1 = X property of 0 and 1) = L.H.S. Hence provedRead more on Sarthaks.com - https://www.sarthaks.com/439644/prove-algebraically-that-x-y-x-z-x-yz

Answer 2

Explanation:

L.H.S. = (X + Y)(X + Z) = XX + XZ + XY + YZ

= X + XZ + XY + YZ (XX = X Indempotence law)

= X + XY + XZ + YZ = X(1 + Y) + Z(X + Y)

= X.1 + Z(X + Y) (1 + Y = 1 property of 0 and 1)

= X + XZ + YZ) (X . 1 = X property of 0 and 1)

= X(1 + Z) + YZ

= X.1 + YZ (1 + Z = 1 property of 0 and 1)

= X.1 + YZ (X . 1 = X property of 0 and 1)

= L.H.S. Hence proved

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