prove algebraically that the NAND operation is not distributive over AND operation
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Answer:
NAND and AND Command
Explanation:
a) x NAND y truth table is as follows: x y x nand y 0 0 1 0 1 1 1 0 1 1 1 0 b) Yes,It is commutative Proof: commutative means x nand y =y nand x let say x=0,y=1 L.H.
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