Question

Prove an activity to = to study the reaction between zinc and dilute hydrochloric acid

Answer 1

Answer:

Zn + HCl ------> ZnCl2 + H2

this is an example of displacement reaction

Answer 2

✰ Answer:-

Aim:-

To Study The Reaction Between Zinc And Dilute Hydrochloric Acid.

Materials Required:-

• Zinc granules
• Conical flask cork
• Glass cube
• Dilute hydrochloric acid

Procedure:-

1. Take a conical flask. Fit it with a cork and a glass tube through the cork.

2. Put a few zinc granules in the flask. Add the dilute hydrochloric acid or sulphuric acid into it.

Caution:-

Handle the acid with care. Direct contact with acid may cause skin irritation and burns.

Observations:-

• Bubbles appear around the zinc granules.

• The flask becomes warm.

$\frac{Zinc \;+\;Hydrochloric \;acid}{Reactants} => \frac{Zinc\;chloride\;+\;Hydrogen}{Products}$

Conclusions:-

• Zinc reacts with dilute hydrochloric acid to form hydrogen gas which appears as bubbles.

• Heat is produced during the reaction causing warming of the flask.

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   Hence, its done!

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