Math, asked by tisyavenkateshiyer1, 9 months ago

prove : angle AOB = 90
triangle AOD is congruent to triangle COD
AB=CD​

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Answered by meestib2004
0

Answer:

proved

Step-by-step explanation:

since ∆ Aod is congruent to ∆ cod

so angle Aod is equal to angle cod

since line OD is bisecting line AC so it's a bisector as well as perpendicular to AC since it is a straight line.(180°)

now, in ∆ AOB n∆ COB

AB = CB given

OB=OB common side

AO=OC

so both triangles are congruent

so angle aob=cob

since angle aod is 90°

so angle aob is 90° as bd is straight line and perpendicular to AO proved above

AOD+AOB=180°

90°+AOB=180

AOB= 90°

Answered by sharmalata923
0

Answer:

this ia not right answer

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