prove : angle AOB = 90
triangle AOD is congruent to triangle COD
AB=CD
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proved
Step-by-step explanation:
since ∆ Aod is congruent to ∆ cod
so angle Aod is equal to angle cod
since line OD is bisecting line AC so it's a bisector as well as perpendicular to AC since it is a straight line.(180°)
now, in ∆ AOB n∆ COB
AB = CB given
OB=OB common side
AO=OC
so both triangles are congruent
so angle aob=cob
since angle aod is 90°
so angle aob is 90° as bd is straight line and perpendicular to AO proved above
AOD+AOB=180°
90°+AOB=180
AOB= 90°
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this ia not right answer
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