Question

Prove angle BAD: angle ADB=3:1

Answer 1

Answer:

Let ∠ADB=x

In △ACD,AC=CD

⇒∠CAD=∠CDA=x

and, ∠ACB=∠CAD+∠CDA=x+x=2x

⇒∠BAC=∠ACB=2x.(∵ In ABC,AB=BC)

∴∠BAD=∠BAC+∠CAD

=2x+x=3x

And, ∠ADB∠BAD=x3x=13

i.e., ∠BAD:∠ADB=3:1 [henceproved

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