prove angle of friction is equal to angle of riposed ?
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tan a=fL/N=u. sN/N =u.s - - - - - angle of friction
fL=u. sN
N=mgcosb
fL=mgsinb
So, tan b=fL/N=u. sN/N =u. s
So angle of friction is equal to angle of repose
Actually, I don't know how to attach an image so I can't show you the diagram
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