Prove area of a triangle is 180degree
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Given:-
△ABC with ∠1 , ∠2 & ∠3
To Prove:-
∠1 + ∠2 + ∠3 = 180°
Construction:-
Draw XY parallel to BC
Proof:-
XAY is a line
∠1 + ∠4 + ∠5 = 180° [Straight line] > (1)
XY || BC
∴ ∠2 = ∠4 [A.I.A] > (2)
∠3 = ∠5 [A.I.A] > (2)
Using (1) & (2)
∠1 + ∠2 + ∠3 = 180°
Hope my answer helps you :)
Regards,
Shobana
^_^
△ABC with ∠1 , ∠2 & ∠3
To Prove:-
∠1 + ∠2 + ∠3 = 180°
Construction:-
Draw XY parallel to BC
Proof:-
XAY is a line
∠1 + ∠4 + ∠5 = 180° [Straight line] > (1)
XY || BC
∴ ∠2 = ∠4 [A.I.A] > (2)
∠3 = ∠5 [A.I.A] > (2)
Using (1) & (2)
∠1 + ∠2 + ∠3 = 180°
Hope my answer helps you :)
Regards,
Shobana
^_^
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