prove area of equilateral triangle is √3/4a square,where a is the side of triangle
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Proof:
Step 1: Since all the 3 sides of the triangle are same,
AB = BC = CA = a
Step 2: Find the altitude of the △ABC.
Draw a perpendicular from point A to base BC, AD ⊥ BC
By using Pythagoras theorem
In △ ADC
h2 = AC2 - DC2
= a2 - (a2)2 [Because, DC = a2 ]
= a2 - a24
h = 3√a2
Step 3: We know that, Area of a triangle = 12 * Base * Height
= 12 * a * 3√a2
= 3√4a2
The area of a equilateral triangle = 3√4a2.
Step-by-step explanation:
Step 1: Since all the 3 sides of the triangle are same,
AB = BC = CA = a
Step 2: Find the altitude of the △ABC.
Draw a perpendicular from point A to base BC, AD ⊥ BC
By using Pythagoras theorem
In △ ADC
h2 = AC2 - DC2
= a2 - (a2)2 [Because, DC = a2 ]
= a2 - a24
h = 3√a2
Step 3: We know that, Area of a triangle = 12 * Base * Height
= 12 * a * 3√a2
= 3√4a2
The area of a equilateral triangle = 3√4a2.
Step-by-step explanation:
DhruvRathee:
thx
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