prove area of four walls of room
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area of four walls of a room = lateral surface area = 2h( l+b )
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four walls of room contain 2pair of congruent rectangle.
so area of one pair rectangle = 2lh
area of another pair of rectangle = 2bh
area of 4 walls of room =2lh+2bh
=2h (l+b)
:-)hope it helps u.
so area of one pair rectangle = 2lh
area of another pair of rectangle = 2bh
area of 4 walls of room =2lh+2bh
=2h (l+b)
:-)hope it helps u.
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