Math, asked by KunalDuttaTSS, 1 year ago

prove arg z1 - arg z2 = π/2, if |z1+z2|=|z1|+|z2|

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Answered by vangauss

argz1-argz2 is the angle between z1 and z2

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KunalDuttaTSS: Thank you sooooooooooooooooo much, worked hard to find it on internet but was unsuccessful, tomorrow is my exam and I'm just thankful to you again

vangauss: no problem, all the best

vangauss: kunal i think the question is wrong ,argz1-argz2 should be zero. in my answer the right hand side when squared has an additional term of 2*z1*z2 which i forgot to add, now when you solve you get cos(theta)=1 so angle must be 0 not pi/2

KunalDuttaTSS: i don't know, it maybe wrong cause i wasn't able to solve that too and it was my question paper of Quarterly Examination

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prove arg z1 - arg z2 = π/2, if |z1+z2|=|z1|+|z2|​

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prove arg z1 - arg z2 = π/2, if |z1+z2|=|z1|+|z2|